Question 1

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waecmaths question: 

Simplify: $10\tfrac{2}{5}-6\tfrac{2}{3}+3$

Option A: 

$6\tfrac{4}{15}$

Option B: 

$6\tfrac{11}{15}$

Option C: 

$7\tfrac{4}{15}$

Option D: 

$7\tfrac{11}{15}$

waecmaths solution: 

$\begin{align}  & 10\tfrac{2}{5}-6\tfrac{2}{3}+3=\tfrac{52}{5}-\tfrac{20}{3}+\tfrac{3}{1} \\ & =\tfrac{152-100+45}{15} \\ & =\tfrac{97}{15} \\ & =6\tfrac{7}{15} \end{align}$

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