Question 1

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Jambmaths question: 

Evaluate 21.05347 – 1.6324 × 0.43 to 3 decimal places

Option A: 

20.980

Option B: 

20.351

Option C: 

20.981

Option D: 

20.352

Jamb Maths Solution: 

$\begin{align}  & \text{Use the rules of BODMAS} \\ & 21.05347-1.6324\times 0.43=21.05347-0.701932 \\ & \text{         }=20.351538 \\ & \text{                                    }\approx 20.352\text{       (3}\text{.decimal places)} \\\end{align}$

Year of Exam: 

Comments

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