Question 10

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Jambmaths question: 

If $X=\{{{n}^{2}}+1:n=0,2,3\}$and $Y=\{n+1:n=2,3,5\}$ find $X\cap Y$

Option A: 

{1, 3}

Option B: 

{5, 10}

Option C: 

$\varnothing $

Option D: 

{4, 6}

Jamb Maths Solution: 

$\begin{align}  & X=\{1,5,10\} \\ & Y=\{3,4,6\} \\ & X\cap Y=\{\}\text{or }\varnothing  \end{align}$

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