Question 10

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Jambmaths question: 

If $x=\{{{n}^{2}}+1:\text{ }n\text{ is a positive and }1\le n\le 5\}$

$y=\{5n:n\text{ is a positive integer and }1\le n\le 5\}$

find $x\cap y$

Jamb Maths Solution: 

$\begin{align}  & x=\{2,5,10,17,26\} \\ & y=\{5,10,15,20,25\} \\ & x\cap y=\{5,10\} \\\end{align}$

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