Question 10

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Jambmaths question: 

In a class of 46 students, 22 play football and 26 play volleyball. If 3 students play both games, how many play neither?

Option A: 

1

Option B: 

2

Option C: 

3

Option D: 

4

Jamb Maths Solution: 

$\begin{align}  & n(\xi )=46 \\ & n(F)=22 \\ & n(V)=26 \\ & n(F\cap V)=3 \\ & n(F\cap {{V}^{1}})=22-3=19 \\ & n({{F}^{1}}\cap V)=26-3=23 \\ & n{{(F\cup V)}^{1}}=x \\ & n(\xi )=n(F\cap {{V}^{1}})+n(F\cap V)+n({{F}^{1}}\cap V+n{{(F\cup V)}^{1}} \\ & 46=19+3+23+x \\ & 46=45+x \\ & x=1 \\\end{align}$

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