Question 11

loading...

Prev/Next links

waecmaths question: 

In the diagram, $QR\parallel ST,\text{ }\left| PQ \right|=\left| PR \right|$ $\text{ and }\angle PST={{75}^{{}^\circ }}$. find the value of y

waecmaths solution: 

$\begin{align}  & \angle PQO=\angle PST={{75}^{\circ }}\text{  }\!\!\{\!\!\text{ corresponding }\angle \text{s }\!\!\}\!\!\text{ } \\ & \angle POQ=PQO={{75}^{\circ }}\text{   }\!\!\{\!\!\text{ base }\angle \text{s of Isso }\vartriangle \text{ }\!\!\}\!\!\text{ } \\ & y={{180}^{\circ }}-\angle POQ\text{     }\!\!\{\!\!\text{ sum of }\angle \text{s on a str}\text{. line }\!\!\}\!\!\text{ } \\ & y={{180}^{\circ }}-{{75}^{\circ }}={{105}^{\circ }} \\\end{align}$

maths year: