Question 11

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waecmaths question: 

Given that x = 2 and $y=-\frac{1}{4}$, evaluate $\frac{{{x}^{2}}y-2xy}{5}$

Option A: 

0

Option B: 

$\tfrac{1}{5}$ 

Option C: 

1

Option D: 

2

waecmaths solution: 

$\frac{{{x}^{2}}y-2xy}{5}=\frac{{{2}^{2}}(-\tfrac{1}{4})-2(2)(-\tfrac{1}{4})}{5}=\frac{1-1}{5}=0$

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