Question 12

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waecmaths question: 

Solve the simultaneous equations$\begin{align}  & x+y=2 \\ & 3x-2y=1 \\\end{align}$

Option A: 

x = 2 and y = 1

Option B: 

x = 1 and y = 1

Option C: 

x = 1 and y = 2

Option D: 

x = –1 and y = 1

waecmaths solution: 

$\begin{align}  & x+y=2---(i) \\ & 3x-2y=1---(ii) \\ & \text{From (i)} \\ & x=2-y \\ & \text{substitute }2-y\text{ for }x\text{ in }(ii) \\ & 3(2-y)-2y=1 \\ & 6-3y-2y=1 \\ & 6-5y=1 \\ & -5y=-5 \\ & y=1 \\ & x=2-1=1 \\ & x=1,y=1 \\\end{align}$

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