Question 13

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waecmaths question: 

If $\tfrac{1}{2}x+2y=3\text{ and }\tfrac{3}{2}x-2y=1$ find (x + y)

Option A: 

3

Option B: 

2

Option C: 

1

Option D: 

0

waecmaths solution: 

$\begin{align}  & \tfrac{1}{2}x+2y=3---(i) \\ & \tfrac{3}{2}x-2y=1---(ii) \\ & \text{Add  (i) and (ii) together} \\ & 2x=4 \\ & x=2 \\ & \text{Substitude }x=2\text{ into (}i) \\ & \tfrac{1}{2}(2)+2y=3 \\ & y=1 \\ & \therefore x+y=2+1=3 \\\end{align}$

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