Question 14

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Jambmaths question: 

Factorize completely $9{{y}^{2}}-16{{x}^{2}}$

Option A: 

$(3y+2x)(3y-4x)$

Option B: 

$(3y+4x)(3y-4x)$

Option C: 

$(3y+4x)(3y+4x)$

Option D: 

$(3y-2x)(3y+4x)$

Jamb Maths Solution: 

$9{{y}^{2}}-16{{x}^{2}}$is a difference of two squares

$9{{y}^{2}}-16{{x}^{2}}={{(3y)}^{2}}-{{(4x)}^{2}}=(3y+4x)(3y-4x)$

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