Question 14

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Jambmaths question: 

Find the value of k if y – 1 is a factor of  ${{y}^{3}}+4{{y}^{2}}+ky-6$ 

Option A: 

–4

Option B: 

Option C: 

0

Option D: 

–6

Jamb Maths Solution: 

$\begin{align}  & \text{let }f(y)={{y}^{3}}+4{{y}^{2}}+ky-6 \\ & \text{since (}y-1)\text{ is a factor, }f(1)=0 \\ & f(1)={{1}^{3}}+4(1)+k(1)-6=0 \\ & 1+4+k-6=0 \\ & k=1 \\\end{align}$

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