Question 14

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Jambmaths question: 

Simplify $1\tfrac{2}{3}+4\tfrac{1}{4}\div 1\tfrac{5}{12}$

Option A: 

$4\tfrac{1}{3}$

Option B: 

$4\tfrac{2}{3}$

Option C: 

$4\tfrac{12}{17}$

Option D: 

$4\tfrac{3}{17}$

Jamb Maths Solution: 

$\begin{align}  & 1\tfrac{2}{3}+4\tfrac{1}{4}\div 1\tfrac{5}{12}=\tfrac{5}{6}+\tfrac{17}{4}\div \tfrac{17}{12} \\ & 1\tfrac{2}{3}+4\tfrac{1}{4}\div 1\tfrac{5}{12}=\tfrac{5}{6}+\tfrac{17}{4}\times \tfrac{12}{17} \\ & 1\tfrac{2}{3}+4\tfrac{1}{4}\div 1\tfrac{5}{12}=\tfrac{5}{6}+3=\tfrac{23}{6} \\\end{align}$

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