Question 14

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waecmaths question: 

Factorize $({{x}^{2}}-2x-3xy+6y)$ completely

Option A: 

$(x-2)(3x-y)$

Option B: 

$(x-3y)(x-2)$

Option C: 

$(x-2)(x+3y)$

Option D: 

$(3x+y)(x-2)$

waecmaths solution: 

$\begin{align}  & ({{x}^{2}}-2x-3xy+6y)=x(x-2)-3y(x-2) \\ & =(x-3y)(x-2) \end{align}$

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