Question 15

loading...

Prev/Next links

Jambmaths question: 

The graph of the function $y={{x}^{2}}+4$and the straight line PQ are drawn to solve the equation ${{x}^{2}}-3x+2=0$. What is the equation PQ

Option A: 

y = 3+2

Option B: 

 y = –3–2

Option C: 

y = 3x – 4

Option D: 

y=3x +4

Jamb Maths Solution: 

$\begin{align}  & \text{Let }{{x}^{2}}+4+{{y}_{1}}={{x}^{2}}-3x+2 \\ & {{y}_{1}}=-3x+2-4 \\ & {{y}_{1}}=-3x-2 \\\end{align}$

Jamb Maths Topic: 
Year of Exam: