Question 15

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waecmaths question: 

Factorize: ${{(2x+3y)}^{2}}-{{(x-4y)}^{2}}$

Option A: 

$(3x-y)(x+3y)$

Option B: 

$(3x+y)(2x-7y)$

Option C: 

$(3x+y)(x-7y)$

Option D: 

$(3x-y)(2x+7y)$

waecmaths solution: 

$\begin{align}  & {{(2x+3y)}^{2}}-{{(x-4y)}^{2}} \\ & \text{Difference of two squares} \\ & =[2x+3y)-(x-4y)][(2x+3y)+(x-4y)] \\ & =[2x+3y-x+4y][2x+3y+x-4y] \\ & =(x+7y)(3x-y) \\ & =(3x-7)(x+7y) \\\end{align}$

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