Question 16

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Jambmaths question: 

Determine the value of x for which $({{x}^{2}}-1)>0$

Jamb Maths Solution: 

$\begin{align}  & {{x}^{2}}-1>0 \\ & {{x}^{2}}>1 \\ & \left| x \right|>1 \\ & -1<x<1 \\\end{align}$

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