Question 16

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waecmaths question: 

Solve the inequality  $3(x+1)\le 5(x+2)+15$

Option A: 

$x\ge -14$

Option B: 

$x\le -14$

Option C: 

$x\le -11$

Option D: 

$x\ge -11$

waecmaths solution: 

$\begin{align}  & 3(x+1)\le 5(x+2)+15 \\ & 3x+3\le 5x+10+15 \\ & 3x+3\le 5x+25 \\ & -2x\le 22 \\ & x\ge -11 \\\end{align}$

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