Question 16

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waecmaths question: 

In the diagram $\angle QPR={{90}^{\circ }}$ , if ${{q}^{2}}=25-{{r}^{2}}$ find the value of p

Option A: 

3

Option B: 

4

Option C: 

5

Option D: 

6

waecmaths solution: 

$\begin{align}  & \text{Using pythagoras theorem} \\ & {{p}^{2}}={{r}^{2}}+{{q}^{2}} \\ & {{p}^{2}}=(25-{{r}^{2}})+{{r}^{2}} \\ & {{p}^{2}}=25 \\ & p=\sqrt{25}=5 \\\end{align}$

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