Question 16

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Jambmaths question: 

Solve the inequality 2 –x > x2

Option A: 

$\text{ }x<-2,\text{ or }x>1$

Option B: 

$x>2\text{ or }x<-1\text{  }$

Option C: 

$-2<x<1$

Option D: 

$-1<x<2\text{ }$

Jamb Maths Solution: 

$\begin{align}  & 2-x>{{x}^{2}} \\ & {{x}^{2}}+x-2<0 \\ & (x+2)(x-1)<0 \\ & x+2<0\text{ or }x-1<0 \\ & x<-2\text{ or }x<1 \\ & \text{The range valid from }-2\text{ to }1 \\ & -2<x<1 \\\end{align}$

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