Question 17

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waecmaths question: 

In the diagram, PQRS is a parallelogram and $\angle QRT={{30}^{\circ }}$. Find x .

 

Option A: 

95o

Option B: 

100o

Option C: 

120o 

Option D: 

150o

waecmaths solution: 

$\begin{align}  & \angle SRQ={{180}^{\circ }}-{{30}^{\circ }}\text{   }\!\!\{\!\!\text{ sum of angles on a straight line }\!\!\}\!\!\text{ } \\ & x=\angle SRQ={{150}^{\circ }}\text{    }\!\!\{\!\!\text{ opposite angle of parallelogram }\!\!\}\!\!\text{ } \\\end{align}$

maths year: