Question 17

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waecmaths question: 

PQRS is a trapezium. $QR\parallel PS,\text{ }\left| QR \right|=6cm,\text{ }\left| PS \right|=10cm\text{ and }\angle QPS={{42}^{\circ }}$


 

 

 

 

Calculate the perpendicular distance between the parallel between the parallel sides

Option A: 

3.35 cm

Option B: 

3.72 cm

Option C: 

4.50 cm

Option D: 

4.62 cm

waecmaths solution: 

$\begin{align}  & AQ=5cm\sin {{42}^{\circ }} \\ & AQ=3.346cm \\ & AQ\approx 3.35cm \\\end{align}$

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