Question 18

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waecmaths question: 

if (xa) is a factor of $bx-ax+{{x}^{2}}-ab$, find the other factor

Option A: 

(x + b)

Option B: 

(xb)

Option C: 

(a + b)

Option D: 

(ab)

waecmaths solution: 

$\begin{align}  & bx-ab+{{x}^{2}}-ax=b(x-a)+x(x-a) \\ & =(b+x)(x-a) \\ & =(x+b)(x-a) \\\end{align}$

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