Question 18

loading...

Prev/Next links

waecmaths question: 

From a point R 300m north of P, a man walks eastwards to a place Q which is 600, from P. Find the bearing of P from Q correct to the nearest degree.

Option A: 

026o

Option B: 

045o

Option C: 

210o

Option D: 

240o

waecmaths solution: 

$\begin{align}  & \sin \theta =\frac{300}{600} \\ & \sin \theta =\frac{1}{2} \\ & \theta ={{\sin }^{-1}}\frac{1}{2}={{30}^{\circ }} \\ & \text{The bearing of }P\text{ from }Q={{180}^{\circ }}+{{60}^{\circ }}={{240}^{\circ }} \\\end{align}$

maths year: 
maths topics: