Question 19

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Jambmaths question: 

Find the mean deviation of 1, 2, 3 and 4

Option A: 

2.5

Option B: 

2.0

Option C: 

1.0

Option D: 

1.5

Jamb Maths Solution: 

$\begin{align}  & mean=\bar{x}=\frac{1+2+3+4}{4}=\frac{10}{4}=2.5 \\ & mean deviation=\frac{\left| 1-2.5 \right|+\left| 2-2.5 \right|+\left| 3-2.5 \right|+\left| 4-2.5 \right|}{4} \\ & mean deviation=\frac{1.5+0.5+0.5+1.5}{4}=\frac{4}{4}=1 \\\end{align}$

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