Question 19

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Jambmaths question: 

Three boys shard some oranges. The first received $\tfrac{1}{3}$of the oranges and second received $\tfrac{2}{3}$ of the remainder. If the third boy received the remaining 12 oranges, how many oranges did they share?

Option A: 

42

Option B: 

48

Option C: 

54

Option D: 

60

Jamb Maths Solution: 

Let all the oranges be x

The first boy took$\tfrac{1}{3}x$, what is left is $\tfrac{2}{3}x$

The second boy took $\tfrac{2}{3}\times \tfrac{2}{3}x=\tfrac{4}{9}x$

The third boy will have $x-\left( \tfrac{1}{3}x+\tfrac{4}{9}x \right)=x-\tfrac{7}{9}x=\tfrac{2x}{9}$

That is $\tfrac{2x}{9}$ represent 12 oranges

The total oranges will be $x=\frac{12\times 9}{2}=54$

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