Question 19

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Jambmaths question: 

Solve the inequality $-6(x+3)\le 4(x-2)$

Option A: 

$x\ge -2$

Option B: 

$x\le -1$

Option C: 

$x\ge -1$

Option D: 

$x\le 2

Jamb Maths Solution: 

$\begin{align}  & -6(x+3)\le 4(x-2) \\ & -6x-18\le 4x-8 \\ & -18+8\le 4x+6x \\ & -10\le 10x \\ & x\ge -1 \\\end{align}$

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