Question 2

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waecmaths question: 

If ${{9}^{(2-x)}}=3$, find x

Option A: 

1

Option B: 

$\tfrac{3}{2}$

Option C: 

2

Option D: 

$\tfrac{5}{2}$

waecmaths solution: 

$\begin{align}  & {{9}^{(2-x)}}=3 \\ & {{3}^{2(2-x)}}={{3}^{1}} \\ & 2(2-x)=1 \\ & 4-2x=1 \\ & 2x=3 \\ & x=\frac{3}{2} \end{align}$

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