Question 2

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Jambmaths question: 

Evaluate $\int_{-4}^{0}{(1-2x)dx}$

Option A: 

–16

Option B: 

20

Option C: 

–20

Option D: 

10

Jamb Maths Solution: 

$\begin{align}  & \int_{-4}^{0}{(1-2x)dx}=\left[ x-{{x}^{2}} \right]_{-4}^{0} \\ & =\left[ 0-0 \right]-\left[ (-4)-{{(-4)}^{2}} \right] \\ & =\left[ -4-16 \right]=-20 \end{align}$

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