Question 2

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waecmaths question: 

Solve for x in the equation $\tfrac{3}{5}(2x-1)=\tfrac{1}{4}(5x-3)$

Option A: 

0

Option B: 

1

Option C: 

2

Option D: 

3

waecmaths solution: 

$\begin{align}  & \tfrac{3}{5}(2x-1)=\tfrac{1}{4}(5x-3) \\ & \text{Multiply both sides by }20 \\ & 12(2x-1)=5(5x-3) \\ & 24x-12=25x-15 \\ & -12+15=25x-24x \\ & 3=x \\ & x=3 \\\end{align}$

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