Question 2

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waecmaths question: 

Factorise $x+y-ax-ay$

Option A: 

$(x-y)(1-a)$

Option B: 

$(x+y)(1+a)$

Option C: 

$(x+y)(1-a)$

Option D: 

$(x-y)(1+a)$

waecmaths solution: 

$\begin{align}  & x+y-ax-ay=(x+y)-a(x+y) \\ & =(1-a)(x+y) \\ & =(x+y)(1-a) \end{align}$

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