Question 20

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waecmaths question: 

In the diagram O is the centre of the circle PQRS and $\angle PSR={{86}^{\circ }}$, if $\angle POR={{x}^{\circ }}$ find x

Option A: 

274o

Option B: 

172o

Option C: 

129o

Option D: 

86o

waecmaths solution: 

$\begin{align}  & \angle PSR={{86}^{\circ }} \\ & \angle POR=2\angle PSR\text{  }\!\!\{\!\!\text{ }\angle \text{ at centre is 2}\times \angle \text{ at cirum }\!\!\}\!\!\text{ } \\ & \angle POR=2\times {{86}^{\circ }}={{172}^{\circ }} \\ & x={{172}^{\circ }} \\\end{align}$ 

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