Question 20

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Jambmaths question: 

Factorize $4{{x}^{2}}-9{{y}^{2}}+20x+25$

Option A: 

(2x – 3y +5) (2x – 3y –5)

Option B: 

(2x – 3y)(2x + 3y)

Option C: 

(2x –  3y +5) (2x + 3y + 5)

Option D: 

(2x + 5) (2x –  9y –5)

Jamb Maths Solution: 

$\begin{align}  & 4{{x}^{2}}-9{{y}^{2}}+20x+25=4{{x}^{2}}+20x+25-9{{y}^{2}} \\ & =4{{x}^{2}}+10x+10x+25-9{{y}^{2}} \\ & =(2x+5)(2x+5)-9{{y}^{2}} \\ & ={{(2x+5)}^{2}}-9{{y}^{2}} \\ & =(2x+5-3y)(2x+5+3y) \end{align}$

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