Question 20

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Jambmaths question: 

Solve the inequality ${{x}^{2}}+2x>15$

Option A: 

$x<3\text{ or }x>5$

Option B: 

$x>3\text{ or }x<-5$

Option C: 

$-5<x<3$

Option D: 

$x<-3\text{ or }x>5$

Jamb Maths Solution: 

${{x}^{2}}+2x>15$

${{x}^{2}}+2x-15>0$

$(x+5)(x-3)>0$

We need to test and find the range of value for this inequality is true

 

 

x < -5

-5 < x < 3

x > 3

x + 5

+

+

x – 3

+

(x + 5)( x – 3)

+

+

The range is x < -5 and x > 3

Jamb Maths Topic: 
Year of Exam: