Question 22


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Jambmaths question: 

In how many ways can 2 students be seated from a group of 5 students in a debating competition?

Option A: 

10 ways

Option B: 

15 ways

Option C: 

25 ways

Option D: 

20 ways

Jamb Maths Solution: 

The number of possible selection $^{5}{{C}_{2}}=\frac{5!}{(5-2)!2!}=\frac{5!}{3!2!}=\frac{5\times 4\times 3!}{3!\times 2\times 1}=10ways$

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