Question 22

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waecmaths question: 

Solve the equation $\frac{2y-1}{3}-\frac{3y-1}{4}=1$

Option A: 

–8

Option B: 

–13

Option C: 

13

Option D: 

19

waecmaths solution: 

$\begin{align}  & \frac{2y-1}{3}-\frac{3y-1}{4}=1 \\ & \frac{4(2y-1)-3(3y-1)}{12}=1 \\ & 8y-4-9y+3=1 \\ & -y-1=12 \\ & y=-13 \\\end{align}$

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