Question 23

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Jambmaths question: 

If a student measured the length of a table to be 2.30m instead of 2.50m. What was the percentage error in measuring the length of the table?

Option A: 

9.0 %

Option B: 

8.0%

Option C: 

7.0%

Option D: 

10.0%

Jamb Maths Solution: 

$\begin{align}  & \text{Actual length}=2.50cm \\ & \text{Measured length}=\text{2}\text{.30cm} \\ & \text{error in measurement}=(2.50-2.30)cm \\ & \text{error in measurement}=0.20cm \\ & Percentage\text{ }error=\frac{0.20}{2.50}\times 100percent=8.0percent \\\end{align}$

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