Question 24

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waecmaths question: 

If cos(x + 40o) = 0.0872, what is the value of x?

Option A: 

85o

Option B: 

75o

Option C: 

65o

Option D: 

45o

waecmaths solution: 

\[\begin{align}  & \cos (x+{{40}^{\circ }})=0.0872 \\ & x+{{40}^{\circ }}={{\cos }^{-1}}(0.0872) \\ & x+{{40}^{\circ }}={{84.9974}^{\circ }} \\ & x+{{40}^{\circ }}\simeq {{85}^{\circ }} \\ & x={{45}^{\circ }} \\\end{align}\]

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