Question 24

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waecmaths question: 

PQRS is a square. If X is the midpoint of PQ, Calculate correct to the nearest degree, $\angle PXS$

Option A: 

53o

Option B: 

55o

Option C: 

63o

Option D: 

65o

waecmaths solution: 

$\begin{align}  & \tan \theta =\frac{opp}{adj}=\frac{a}{{a}/{2}\;} \\ & \tan \theta =2 \\ & \theta ={{\tan }^{-1}}2={{63.43}^{\circ }} \\ & \theta \approx {{63}^{\circ }}\text{ (to the nearest degree)} \\\end{align}$

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