Question 25

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waecmaths question: 

A kite on a taut string of length 50m  inclined at an angle of 54o to the horizontal ground. The height of the kite above the ground is

Option A: 

$50\tan {{36}^{\circ }}$

Option B: 

$50\sin {{54}^{\circ }}$

Option C: 

$50\tan {{54}^{\circ }}$

Option D: 

$50\sin {{36}^{\circ }}$

waecmaths solution: 

$h=BC=50\sin {{54}^{\circ }}$

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