Question 25

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Jambmaths question: 

The sum to infinity of the series $1+\tfrac{1}{3}+\tfrac{1}{9}+\tfrac{1}{27}+---$ is

Option A: 

$\tfrac{11}{3}$

Option B: 

$\tfrac{10}{3}$

Option C: 

$\tfrac{5}{2}$

Option D: 

$\tfrac{3}{2}$

Jamb Maths Solution: 

$\begin{align}  & a=1,\text{ }r=\tfrac{1}{3} \\ & {{S}_{\infty }}=\frac{a}{1-r}=\frac{1}{1-\tfrac{1}{3}} \\ & {{S}_{\infty }}=\frac{1}{\tfrac{2}{3}}=\frac{3}{2} \\\end{align}$

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