Question 28

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waecmaths question: 

Factorize the expression $am+bn-an-bm$

Option A: 

$(a-b)(m+n)$

Option B: 

$(a+b)(m-n)$

Option C: 

$(a+b)(m-n)$

Option D: 

$(a+b)(m+n)$ 

waecmaths solution: 

$\begin{align}  & am+bn-an-bm \\ & am-an-mb+bn \\ & a(m-n)-b(m-n) \\ & (a-b)(m-n) \\ \end{align}$

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