Question 28

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Jambmaths question: 

If ${{\log }_{10}}2=0.3010$ and${{\log }_{10}}3=0.4771$, evaluate ${{\log }_{10}}4.5$

Option A: 

0.4471

Option B: 

0.3010

Option C: 

0.6532

Option D: 

0.9542

Jamb Maths Solution: 

$\begin{align}  & {{\log }_{10}}4.5={{\log }_{10}}\tfrac{9}{2} \\ & ={{\log }_{10}}{{3}^{2}}-{{\log }_{10}}2 \\ & =2\log 3-{{\log }_{10}}2 \\ & =2(0.4771)-0.3010 \\ & =0.9542-0.3010 \\ & =0.6532 \end{align}$

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