Question 29

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waecmaths question: 

A ship sails x km due east to a point E and continues x km due north to F . Find the bearing of F from the starting point.

Option A: 

045o

Option B: 

090o

Option C: 

135o

Option D: 

225o

waecmaths solution: 

$\begin{align}  & \tan \theta =\frac{opp}{adj}=\frac{x}{x}=1 \\ & \theta ={{\tan }^{-1}}(1)={{45}^{\circ }} \\ & \angle NCF={{90}^{\circ }}-{{45}^{\circ }}={{45}^{\circ }} \\ & \text{The bearing of }F\text{ from the start point is 04}{{\text{5}}^{\circ }} \\\end{align}$

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