Question 29

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Jambmaths question: 

Evaluate $\int{\sin 4xdx}$

Option A: 

$-\tfrac{3}{4}\cos 4x+c$

Option B: 

$-\tfrac{1}{4}\cos 4x+c$

Option C: 

$\tfrac{1}{4}\cos 4x+c$

Option D: 

$\tfrac{3}{4}\cos 4x+c$

Jamb Maths Solution: 

$\begin{align}  & Note:\int{\sin axdx}=-\frac{1}{a}\cos ax+c \\ & \int{\sin 4xdx}=-\frac{1}{4}\cos 4x+c \\\end{align}$

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