Question 3

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Jambmaths question: 

The sum of the interior angles of a pentagon is 6x + 6y. Find y in term of x 

Option A: 

y = 90 – x

Option B: 

y = 150 – x

Option C: 

y = 60 – x

Option D: 

y = 120 – x

Jamb Maths Solution: 

 $\begin{align}  & \text{Pentagon has 5 sides} \\ & \text{The total interior angles in a pentagon will be} \\ & (5-2)\times {{180}^{o}}={{540}^{o}}\text{     }\left| (n-2){{180}^{o}} \right. \\ & 6x+6y={{540}^{o}} \\ & x+y={{90}^{o}} \\ & y={{90}^{o}}-{{x}^{o}} \\\end{align}$

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