Question 3

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waecmaths question: 

Evaluate $7\tfrac{1}{2}-(2\tfrac{1}{2}+3)\div \tfrac{33}{2}$, correct to the nearest whole number

Option A: 

33

Option B: 

8

Option C: 

7

Option D: 

0

waecmaths solution: 

$\begin{align}  & 7\tfrac{1}{2}-(2\tfrac{1}{2}+3)\div \tfrac{33}{2}=\tfrac{15}{2}-(\tfrac{5}{2}+3)\times \tfrac{2}{33} \\ & 7\tfrac{1}{2}-(2\tfrac{1}{2}+3)\div \tfrac{33}{2}=\tfrac{15}{2}-(\tfrac{5+6}{3})\times \tfrac{2}{33} \\ & 7\tfrac{1}{2}-(2\tfrac{1}{2}+3)\div \tfrac{33}{2}=\tfrac{15}{2}-(\tfrac{11}{2}\times \tfrac{2}{33}) \\ & 7\tfrac{1}{2}-(2\tfrac{1}{2}+3)\div \tfrac{33}{2}=\tfrac{15}{2}-\tfrac{1}{3} \\ & 7\tfrac{1}{2}-(2\tfrac{1}{2}+3)\div \tfrac{33}{2}=\tfrac{45-2}{6}=\tfrac{43}{6}=7.1667 \\ & \text{To the nearest whole number} \\ & 7\tfrac{1}{2}-(2\tfrac{1}{2}+3)\div \tfrac{33}{2}\approx 7 \\\end{align}$

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