Question 30

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waecmaths question: 

If $2{{\log }_{x}}(3\tfrac{3}{8})=6$ find the value of x

Option A: 

$\tfrac{3}{2}$

Option B: 

$\tfrac{4}{3}$

Option C: 

$\tfrac{2}{3}$

Option D: 

$\tfrac {1}{2}$

waecmaths solution: 

$\begin{align}  & 2{{\log }_{x}}(3\tfrac{3}{8})=6 \\ & {{\log }_{x}}(\tfrac{27}{8})=3 \\ & {{x}^{3}}=\frac{27}{8} \\ & {{x}^{3}}={{\left( \frac{3}{2} \right)}^{3}} \\ & x=\frac{3}{2} \\\end{align}$

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