Question 30

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waecmaths question: 

The nth term of the sequence  –2, 4, –8, 16,…. Is given by

Option A: 

${{T}_{n}}={{2}^{n}}$

Option B: 

${{T}_{n}}={{(-2)}^{n}}$

Option C: 

${{T}_{n}}=(-2n)$

Option D: 

${{T}_{n}}={{2}^{n}}$

waecmaths solution: 

$\begin{align}  & {{T}_{1}}=-2={{(-2)}^{-1}} \\ & {{T}_{2}}=4={{(-2)}^{2}} \\ & {{T}_{3}}=8={{(-2)}^{3}} \\ & {{T}_{n}}={{(-2)}^{n}} \\\end{align}$

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