Question 31

loading...

Prev/Next links

Jambmaths question: 

If the mid point of PQ is (2,3) and the point P is (-2,1). Find the coordinate of the point

Option A: 

(5,6) 

Option B: 

(0,4)

Option C: 

(6,5)

Option D: 

(8,6)

Jamb Maths Solution: 

\[\begin{align}  & \text{The coordinate of the mid point of a line segment is given as }(x,y)=\left( \frac{{{x}_{1}}+{{x}_{2}}}{2},\frac{{{y}_{1}}+{{y}_{2}}}{2} \right) \\ & M=(x,y)=(2,3) \\ & P=({{x}_{1}},{{y}_{1}})=(-2,1) \\ & Q=({{x}_{2}},{{y}_{2}})=(?,?) \\ & (2,3)=\left( \frac{-2+{{x}_{2}}}{2},\frac{1+{{y}_{2}}}{2} \right) \\ & 2=\frac{-2+{{x}_{2}}}{2} \\ & 4=-2+{{x}_{2}} \\ & {{x}_{2}}=6 \\ & \frac{1+{{y}_{2}}}{2}=3 \\ & 1+{{y}_{2}}=6 \\ & {{y}_{2}}=5 \\ & ({{x}_{2}},{{y}_{2}})=(6,5) \\ & \text{The coordinate of }Q\text{ is (6,5)} \\\end{align}\]

Jamb Maths Topic: 
Year of Exam: