Question 31

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waecmaths question: 

A fair die is thrown two times. What is the probability that the sum of the scores is at least 10?

Option A: 

$\frac {5}{36}$

Option B: 

$\frac {1}{6}$

Option C: 

$\frac {5}{18}$

Option D: 

$\frac {2}{3}$

waecmaths solution: 

$\begin{align}  & Possible\text{ }outcomes=(5,5)(6,4)(4,6),(5,6),(6,5),(6,6) \\ & n(possible\text{ }outcome)=6 \\ & n(total\text{ }possible\text{ }outcome)=36 \\ & \Pr (of\text{ }atleast\text{ }sum\text{ }of\text{ }ten)=\frac{6}{36}=\frac{1}{6} \\\end{align}$

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